Figuring out memory leak

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  Hello Zin,
  
  This is a difficult question to answer without knowing the application and what it's been doing. If you want, you can send the profiler results to us at support@red-gate.com and we can try to have a look and offer some suggestions for you.

  Brian Donahue August 17, 2005 13:13

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  It took me a while to collect the data and the result file is ~80Mb, it won't work via emailing

  Zin August 17, 2005 15:14

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  Hello Zin,
  
  Give me until tomorrow and I will set up a private FTP account for you on our FTP server.

  Brian Donahue August 18, 2005 13:11

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  Hello Zin,
  
  If you're still interested, I've set up an FTP directory for you. Your username and password have been sent via email.

  Brian Donahue August 24, 2005 09:29

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  I have the samilar question, is there a guide line to pinpoint the memory leak cause using the memory profiler result? thanks

  caroline August 26, 2005 11:32

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  I'm under the impression that this depends a lot on the nature of the application. You need to know what objects should be 'live' and which ones should be disposed. Without that information, you're left squarely in the dark.
  
  The starting point is normally to look at the 'all objects' tab and find the number of objects that have been allocated and compare that to the live count.

  Brian Donahue August 26, 2005 11:53

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  Brian Donahue wrote:

  I'm under the impression that this depends a lot on the nature of the application. You need to know what objects should be 'live' and which ones should be disposed. Without that information, you're left squarely in the dark.
  
  The starting point is normally to look at the 'all objects' tab and find the number of objects that have been allocated and compare that to the live count.

  
  'live' means the object is referenced and cannot be collected, right? how if an object is already out of calling range, such as a private string?

  caroline August 26, 2005 12:20

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  Hello Caroline,
  
  As far as I'm aware, a live object is an object which still has a pointer to it on the program's stack. I'm sure it's more complex than that, though.

  Brian Donahue August 30, 2005 05:20

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