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Errors on partition functions with NULL boundaries

I ran into an issue with SQL Compare, both versions 11.4.4 and 11.4.3 where comparing databases fails when there is a NULL boundary value for a partition function in the database.

For example:

create partition function test_pf (int) as range LEFT for values((NULL))
breno
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  • Anu D
    Hi Breno,

    I am assuming that the issue is similar to your latest post.

    I have logged a support ticket and will email you shortly!
    Anu D
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